What is the mole fraction of I2 in a solution made by dissolving 63.1 g of I2 in 245 g of hexane, C6H14?

Answer 1

molar mass I₂ = 253.8 g / mol

molar mass hexane (C₆H₁₄) = 86.2 g / mole

moles I₂ = 63.1 g x 1 mol / 253.8 g = 0.249 mols

moles hexane = 245 g x 1 mol / 86.2 g = 2.84 mols

Total moles = 0.249 + 2.84 = 3.09 mols

Mole fraction I₂ = 0.249 mols / 3.09 mols = 0.081