CaCO3 + 2 HCl --> CaCl2 + H2O + CO2 How much 0.80 M HCl would be needed to dissolve a CaCO3 pearl which weighs 4.0 grams?

Answer 1

CaCO₃ + 2HCl ==> CaCl₂ + H₂O + CO₂ .. balanced equation

molar mass CaCO₃ = 100. g / mole

moles CaCO₃ present = 4.0 g x 1 mol / 100. g = 0.040 moles

moles HCl required = 0.040 mol CaCO₃ x 2 mol HCl / mol CaCO₃ = 0.080 mols HCl

Volume HCl required = 0.080 mols x 1 L / 0.80 mol = 0.10 L = 100 mls