Determine z-scores to standardize the normal distribution
(57000-54800)/2600 ≈ 0.84
(54000-54800)/2600 ≈ -0.31
Determine the percentage between the z-scores
P(-0.31<Z<0.84) = P(Z<0.84)-P(Z<-0.31) ≈ 0.7995-0.3783 = 0.4212 ≈ 42.1%
Therefore, 42.1% of people in this profession earn annual salaries between $54,000 and $57,000.
Hope this helped! Make sure to use a z-table to determine the percentage value.

AJ L.
04/30/23