
William W. answered 04/28/23
Experienced Tutor and Retired Engineer
Make a point D:
∠BAD = ∠BAC + ∠CAD = 12 + 58 = 70°
Using ΔCAD (a right triangle), and cos(θ) = adjacent/hypotenuse:
cos(58°) = AD/101
Segment AD = 101cos(58°) = 53.52 m
Now using ΔBAD (another right triangle), and cos(θ) = adjacent/hypotenuse:
cos(70°) = 53.52/x
x = 53.52/cos(70°) = 156.5 m