What is E at 25 °C for the reaction described by Zn(s) | Zn²⁺ (0.10 M) || Cu²⁺ (1.00 M) | Cu(s)? The standard cell potential for the reaction is +1.100 V.

Answer 1

Again, as in your previous question, note that the concentrations of ions are NOT 1 M, so we will use the Arrhenius equation:

Ecell = Eº - RT/nF ln Q and at 298K this reduces to...

Ecell = Eº - 0.0592 / n log Q

Ecell = ?

Eº = 1.100

n = 2 mol electrons

Q = [Cu2+] / [Zn2+] = 1.00 / 0.10 = 10

Ecell = 1.100 - 0.0296 log 10

Ecell = 1.100 - 0.0296

Ecell = 1.070 V

(be sure to check all of the math)