J.R. S. answered 04/25/23
Ph.D. University Professor with 10+ years Tutoring Experience
This question is about the Born Haber cycle. If not familiar, please investigate it.
M(s) + X2(g) ==> MX2 ∆Hf = -987 kJ/mol
M(s) => M(g) ∆Hsub = 125 kJ/mol
M(g) => M+(g) IE1 = 677 kJ/mol
M+(g) => M2+(g) IE2 = 1390 kJ/mol
X2(g) => 2X(g) BE = 201 kJ/mol
2X(g) => 2X-(g) EA = -351 kJ/mol x 2 = -752 kJ
∆Hf = ∆Hsub + IE + BE + EA + LE
Solve for LE (lattice energy):
-987 = 125 + 677 + 1390 + 201 -752 + LE
LE = -2628 kJ/mol