Determine the molarity of a solution that is prepared by dissolving 60 grams of LiBr in 500 mL of solution.

Answer 1

molar mass LiBr = 86.85 g / mole

moles LiBr used = 60 g x 1 mol / 86.85 g = 0.691 moles

Molarity = moles/liter = 0.691 moles / 500 ml x 1000 ml / L = 1.382 M = 1 M (to 1 sig. fig.)