If you start with 3.73 g of NH4NO3, how many grams of NH3 can you make?

Question

2 NH₄NO₃ + Ca(OH)₂ -> 2NH₃ + 2 H₂O + Ca(NO₃)₂

Answer 1

2 NH₄NO₃ + Ca(OH)₂ ==> 2NH₃ + 2 H₂O + Ca(NO₃)₂ .. balanced equation

molar mass NH₄NO₃ = 80.04 g / mol

molar mass NH₃ = 17.03 g / mol

moles NH₄NO₃ used = 3.73 g NH₄NO₃ x 1 mol / 80.04 g = 0.0466 mols

moles NH₃ produced = 0.0466 mols NH₄NO₃ x 2 mol NH₃ / 2 mol NH₄NO₃ = 0.0466 mol NH₃

mass NH₃ produced = 0.0466 mol NH₃ x 17.03 g / mol = 0.794 g NH₃ (to 3 sig. figs.)