Using the mass percentage of oxygen in KClO3 (43.4%), calculate the maximum amount of oxygen in grams you could produce with 1.503g of KClO3 that you heat.

Answer 1

First, you need to write the balanced equation for production of O₂ from KClO₃

2KClO₃ ==> 2KCl + 3O₂(g) .. balanced equation

Conservation of mass tells us that mass of reactant (1.503 g) must = mass of products (?). All of the oxygen in KClO₃ will end up as oxygen (O₂) in the product

The question is a little vague in as much as it doesn't distinguish between elemental oxygen (O) and diatomic oxygen (O₂).

43.4% x 1.503 g = 0.6523 g of O in 1.503 g of KClO₃

0.6523 g O x 2 = 1.305 g O₂