J.R. S. answered 04/16/23
Ph.D. University Professor with 10+ years Tutoring Experience
Figure out moles of electrons transferred by the given charge that deposited 2.159 g Ag.
Ag+ + 1e- ==> Ag(s)
2.159 g Ag x 1 mol / 107.9 g = 0.0200 moles Ag = 0.0200 moles of electrons
Apply this to the deposition of Cu from Cu2+
Cu2+ + 2e- ==> Cu(s)
0.0200 mols e- x 1 mol Cu2+ / 2 mol e- = 0.0100 mols Cu(s)
0.0100 mols Cu x 63.5 g / mol = 0.635 g Cu = ANSWER A