Assuming conditions are met, we can calculate the z-statistic:
z = (p̂-p0)/√[p0(1-p0)/n] = (36/121 - 0.3)/√[0.3(1-0.3)/131] ≈ -0.06
Also, assuming a significance level of α=0.05:
P(Z<z) = P(Z<-0.06) ≈ 0.4761 > 0.05
Hence, we fail to reject the null hypothesis, which tells us that the true population proportion is most likely less than p=0.3
Hope this helped!