A 90% confidence interval for p, based on a random sample of n = 400 observations from a binomial population with x = 375 successes.

Question

Find the necessary confidence interval for the binomial proportion p. (Round your answers to three decimal places.)

Answer 1

CI = 375/400 ± 1.645√[(375/400)(1-375/400)/400] ≈ {0.918,0.957}

Hence, you would be 90% confident that the true population proportion is contained within the interval {0.918,0.957}

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