Determine the equilibrium constant for a reaction at 230.0 K if ∆G° =-12.20 kJ/mol. (R = 8.314 J/mol ･ K)

Question

Determine the equilibrium constant for a reaction at 230.0 K if ∆G° =-12.20 kJ/mol. (R = 8.314 J/mol ･ K)

Answer 1

∆Gº = -RT ln K

∆Gº = -12.20 kJ/mol

R = 8.314 J/molK = 0.008314 kJ/molK (note: change units to agree with those of ∆Gº)

T =230K

K = ?

-12.20 kJ/mol = -(0.008314 kJ/molK)(230K) ln K

-12.20 kJ/mol = -1.91 ln K

ln K = 6.39

K = 594