What is the change in enthalpy when 1.50 moles of H2 are reacted with an excess O₂ of according to the following balanced chemical reaction: 2H₂(g)+O₂(g)→2H₂O(l) ∆H=-572 kj

Answer 1

Amy, I'm a little surprised that you haven't figured out how to do these problems since we have answered many of these same questions for you in the past. Did you try to do this problem? Look at the balanced equation and see that TWO moles of H2(g) react and produces 572 kJ of energy. So, how much energy would ONE AND ONE HALF moles of H2(g) produce? It isn't that difficult, is it?

2 mols H2 produces 572 kJ

1 mol H2 produces 286 kJ

3 mols H2 produces 858 kJ

etc.....

Give it a try and see if you can come up with 429 kJ