What volume of 0.100 M KOH is needed to react completely with 17.7 mL of 0.300 M H2SO4 ?

Question

Balanced equation

H2SO4(aq)+2KOH(aq)⟶2H2O(l)+K2SO4(aq)

Answer 1

To find the volume of KOH, we need to know the moles KOH used in the reaction.

H₂SO₄ + 2KOH ==> K₂SO₄ + 2H2O .. balanced equation

moles H₂SO₄ present = 17.7 ml x 1 L / 1000 ml x 0.300 mol / L = 5.31x10^-3 moles

To find mols KOH, use dimensional analysis and mol ratios in the balanced equation:

mols KOH = 5.31x10^-3 mol H₂SO₄ x 2 mol KOH / 1 mol H₂SO₄ = 0.01062 mol KOH used

To find the volume of KOH, we use the fact that it has 0.100 moles / Liter (0.100 M):

0.01063 mol KOH x 1 L / 0.100 mol = 0.106 L KOH = 106 mls KOH