What concentration (in M) of the strong base NaOH is required to obtain an aqueous solution with the pH value of 13.2?

Question

What concentration (in M) of the strong base NaOH is required to obtain an aqueous solution with the pH value of 13.2?

Answer 1

The strong base NaOH will dissociate completely to form Na⁺ and OH^-.

pH = 13.2

pH + pOH = 14, so we can calculate pOH

pOH = 14 - 13.2 = 0.8

From this we can calculate the [OH^-] since pOH = -log [OH^-]

[OH^-] = 1x10^-0.8 = 1.58x10^-1 = 0.158 M NaOH