Express the confidence interval 12.6%<p<24.4% 12.6 % < p < 24.4 % in the form of ˆ p ±ME ˆ p ± M E .

Answer 1

p would be the average of the bounds, or (12.6%+24.4%)/2 = 37%/2 = 18.5%

The margin of error will be the value between either bound and p, so you can do 24.4%-18.5%=5.9% or 18.5%-12.6%=5.9%

Thus, the confidence interval can be written as p±ME = 18.5% ± 5.9% = 0.185 ± 0.059

Hope this helped!