J.R. S. answered 03/29/23
Ph.D. University Professor with 10+ years Tutoring Experience
From the table of standard reduction potentials, we have...
Ti2+(aq) + 2e- ==> Ti(s) .. Eº = -1.63 V (anode)
Sn2+(aq) + 2e- ==> Sn(s) .. Eº = -0.14 V (cathode)
Eºcell = cathode - anode
Eºcell = -0.14 - (-1.63)
Eºcell = 1.49 V