J.R. S. answered 03/28/23
Ph.D. University Professor with 10+ years Tutoring Experience
2CO + O2 ==> 2CO2 .. balanced equation
To answer this problem, we will first find the moles of CO and moles of O2 present. From the mol ratio of the balanced equation, we'll determine which reactant is limiting. Using the moles of the limiting reactant, we'll find the moles of CO2 produced and finally convert that to grams of CO2 produced.
Info needed:
molar mass CO = 28.01 g / mol
molar mass O2 = 32.0 g / mol
molar mass CO2 = 44.0 g / mol
moles CO present = 7.10 g CO x 1 mol CO / 28.01 g = 0.253 mols CO
moles O2 present = 7.10 g O2 x 1 mol O2 / 32.0 g = 0.222 mols O2
Since the balanced equation tells us that we need 2 mols CO for every 1 mol O2, CO will be limiting because we don't have twice as many moles as O2.
Moles of CO2 produced = 0.253 mols CO x 2 mols CO2 / 2 mols CO = 0.253 mols CO2
Mass of CO2 = 0.253 mols CO2 x 44.0 g CO2 / mol = 11.1 g CO2 (3 sig. figs.)