finding the Concentration

Question

A 10.0 mL sample of H₂SO₄ is titrated with 0.588 M NaOH. The initial buret volume is 0.05 mL and the final buret volume is 20.99 mL. What is the concentration (mol/L) of the H₂SO₄ sample? Answer to 3 decimal places with no units.

Answer 1

H2SO4 + 2NaOH ==> Na2SO4 + 2H2O

Volume NaOH used = 20.99 ml - 0.05 ml = 20.94 ml

mols NaOH used = 20.94 ml x 1 L / 1000 ml x 0.588 mol / L = 0.01231 mols NaOH

mols H2SO4 present = 0.01231 mols NaOH x 1 mol H2SO4 / 2 mol NaOH = 0.006156 mols H2SO4

Concentration H2SO4 = 0.006156 mols / 10.0 ml x 1000 ml / L = 0.616 mol / L

Answer = 0.616