What is the change in enthalpy of a system at 300 K, ΔS is 30 J/Kmol, and ΔG is at equilibrium?

Answer 1

∆G = ∆H - T∆S

At equilibrium ∆G = 0

T = 300K

∆S = 30 J/Kmol

∆H = ?

0 = ∆H - (300K)(30 J/Kmol)

∆H = 9000 J/mol = 9.0 kJ/mol