J.R. S. answered 03/26/23
Ph.D. University Professor with 10+ years Tutoring Experience
Is the reaction @ equilibrium or not?
Compare Q to Kp:
Q = (PB)3 / (PA) = (0.120)3 / 4/60 = 0.00037 which is much below the Kp of 0.623, so not at equilibrium
∆G = ∆Gº + RT ln Q
First, we must find ∆Gº:
∆Gº = -RT ln K = -(0.008314 kJ/Kmol)(298) ln 0.623 = 1.17 kJ/mol
∆G = ∆Gº + RT ln Q
∆G = 1.17 kJ/mol + (0.008314 kJ/Kmol)(298) ln 0.00037
∆G = 1.17 - 19.58
∆G = -18.4 kJ/mol