Neeta G. answered 08/12/23
Experienced Statistics and Math teacher for High School and Colle
The best estimate for p is, p^=x/n=96/600=0.16
The standard error=SQRT(p^*(1-p^)/n)=sqrt (.16*(1-.16)/600)=0.01496
The confidence level is 99%.
Hence, alpha=(1-c) =(1-.99)=0.01
alpha/2= 0.005
Z (alpha/2) from the table is=2.58
The margin of error=Z ( for alpha/2= 0.005)*standard error=2.58*0.01496 = 0.0386
Lower bound=p^-Margin of error=.16-0.0386=0.1214
Upper bound=p^+margin of error=.16+0.0386=0.1986