Determine the limiting reagent of MgO(s)+2HCl(aq)= MgCl2(aq)+H2O when there are 1.0g MgO and 76.3g HCl

Answer 1

molar mass MgO = 40.3 g / mol

molar mass HCl = 36.5 g / mol

moles MgO = 1.0 g x 1 mol / 40.3 g = 0.0248 mols MgO (÷1->0.02)

moles HCl = 76.3 g HCl x 1 mol / 36.5 g = 2.09 mols HCl (÷2->1.04)

Since 0.02 is less than 1.04, MgO is the limiting reagent