chemistry 11 grade

Question

0.465 mole sample of gas everts 4.43 atm of pressure in a 2.25 L container. What is temperature of the gas un the container ?

Answer 1

Are you familiar with the Ideal Gas Law PV = nRT? If not, you should learn it well.

P = pressure = 4.43 atm

V = volume in liters = 2.25 L

n = moles of gas = 0465 mols

R = gas constant = 0.0821 Latm/Kmol

T = temperature in Kelvin = ?

So we need to solve for T (temperature)

PV = nRT

(4.43)(2.25) = (0.465)(0.0821)(T)

T = (4.43)(2.25) / (0.465)(0.0821)

T = 261 K

If they want the answer in degrees Celsius, we need to subtract 273 from the Kelvin temperature

T = -12ºC