What is the equation of the line in slope-intercept form that passes through point (4, 5) and is parallel to the line y = −2x − 2?

Answer 1

The parallel line must have a slope of -2. Now we just use (4,5) to calculate the y-intercept.

y = mx+b

y = -2x+b

at (4,5) we get 5 = -2(4) +b which gives b=13

So the equation is y = -2x+13

Answer 2

Start with point-slope form (from Algebra 1)

(y - 5) = -2(x - 4)

Now convert to slope-intercept form.