Raymond B. answered 03/16/23
Math, microeconomics or criminal justice
focus (5,7) directrix y=0
it's an upward opening parabola with line of symmetry x=5
the vertex is midway between the focus and directrix V(5, 3.5)
just one more point and you have the quadratic equation
y = a(x-5)^2 + 7/2.
plug in that point and solve for "a" coefficient of the x^2 term
directly, horizontally, to the right (and left) of the focus is another point on the parabola
to the right is a point with y coordinate = 7, and x coordinate such that x=7+5=12
7 = a(7-5)^2 +3.5
7/2 = 49a
7a = 1/2
a = 1/14
y = (1/14)(x-5)^2 + 7/2 in vertex form
or 1/4p = a where p = 1/2 the distance from focus to directrix
= 1/4(3.5) = 1/14 = a
y =(1/4p)(x-5)^2 +7/2
y = (1/14)(x-5)^2 + 7/2