J.R. S. answered 03/16/23
Ph.D. University Professor with 10+ years Tutoring Experience
When the conditions are constant (no change in temperature or pressure, etc.), the volumes can be used just like we use moles. So, the ratio of moles of H2O to moles CO2 in this case is 3:1. But since each unit of H2O has 2 H, that translates to a ratio of H to C of 6:1. Unfortunately, this does not correspond to any of the options. So, either there is an error in the presentation of the problem, or there is something that unusual that is missing.
In fact, if you take the answer given, and look at the combustion of C4H6, the ratio of H2O to CO2 is NOT 60:20, or 3:1, but is 3:4
C4H6 + 51/2 O2 ==> 4CO2 + 3H2O .. balanced equation for combustion of C4H6 (note ratio of H2O:CO2)