chemistry 11 grade

Question

3.2 moles of carbon dioxide held inside in a 15 L container. How much gas at the same temperature and pressure could be held in a 4.0 L container? Avogadro's Equation needed.

At what temperature would the volume of gas be 0.550 L . if it had volume of 0.432L at -20.0C? Convert -20.0 C to Kelvin. Charles Gas Law needed.

Answer 1

Avogadro's equation for gases: V1/n1 = V2/n2

V1 = initial volume = 15 L

n1 = initial moles = 3.2 mols

V2 = final volume = 4.0 L

n2 = final mols = ?

Solve for n2:

15 L / 3.2 mols = 4.0 L / x mols

x = 0.85 mols

Charles Gas law: V1/T1 = V2/T2

V1 = initial volume = 0.432 L

T1 = initial temperature in Kelvin = -20C + 273 = 253K

V2 = final volume = 0.550 L

T2 = final temperature in Kelvin = ?

Solve for T2:

0.432 L / 253K = 0.550 L / x

x = 322K

x = 322K - 273 = 49ºC