A baseball player has a batting average of 0.43 a) what is the probability that he has exactly 3 hits in the next 8 bats? b) What is his batting expected value?

Question

I worked out part a and got that P(X=3)= 0.2678968901

I do not understand how to find the expected value for his batting.

Answer 1

a) 8C3(.43)^3(.57)^5

b) Expected number of hits in 3 bats out of 8 = np = 8(.43) = 3.42 hits out of 8,