thank you for your question!
in order to find the value here you want to use the equation
x = u + z*o, where u is the mean, z is the z score that goes with the 98th percentile, and o is the standard deviation
the only value that is not given to us directly in the question is the standard deviation, but we can find that using the Q3 value of 1662
1662 = 1454 + 0.6745 * o
o = 308.38
putting it all together then we have
x = 1454 + 2.054*308.38
x = 2087.37
so you would expect the score in the 98th percentile to be about 2087