J.R. S. answered 03/09/23
Ph.D. University Professor with 10+ years Tutoring Experience
Au+(aq) + e- ==> Au(s)
52.0 amps = 52.0 Coulombs(C) / sec
52.0 C / sec x 60 sec / min x 60 min / hr = 187,200 C in the 1 hour
moles of electrons = 187,200 C x 1 mol e- / 96,500 C = 1.94 moles of electrons
moles of Au+ converted to Au(s) = 1.94 mol e- x 1 mol Au / mol e- = 1.94 moles Au
mass of Au deposited = 1.94 mols Au x 197 g / mol = 382 g Au