J.R. S. answered 03/09/23
Ph.D. University Professor with 10+ years Tutoring Experience
∆G = -RT ln K
@2000K
4.71 kJ/mol = -(0.008312 kJ/Kmol x 2000K) ln K
ln K = -0.2833
K = 0.753
@3000K
47.21 kJ/mol = -(0.008314 kJ/Kmol x 3000K) ln K
ln K = -1.893
K = 0.151