J.R. S. answered 03/08/23
Ph.D. University Professor with 10+ years Tutoring Experience
Think about the lab that you did. I'm guessing it was a lab on oxidation and reduction. If you had a solid piece of magnesium (Mg) and some Cu2+ in solution as CuCl2, what do you think might happen? Look up the reduction potentials for both Mg and Cu (Mg2+ and Cu2+). I think you'll see that Cu2+ will be reduced before Mg2+, so that means in the situation you have, Cu2+ will be reduced to Cu(s) and Mg(s) will be oxidized to Mg2+ and go into solution. So the solid Mg will disappear. But you should also see solid copper Cu(s) appear.
Mg(s) + Cu2+(aq) ==> Mg2+(aq) + Cu(s)