Chemistry HW Help

Question

What is the equilibrium constant K at 25 °C for an electrochemical cell when E° = +0.120 V and n = 2? (F = 96500 J/(V• mol), R= 8.314 J/(mol• K))

Answer 1

Refer to the Nernst equation:

Eº = (RT/nF) lnK

0.120 V = (8.314 J / molK x 298K) / (2 mol e- x 96500 J / Vmole e-) ln K

0.120 = 2478 / 193,000 ln K

0.120 = 0.01284 ln K

ln K = 9.35

K = 11,451