J.R. S. answered 03/08/23
Ph.D. University Professor with 10+ years Tutoring Experience
NO3- (aq) + AsH3(s) -> NH3(g) + As(s)
NO3-(aq) ==> NH3(g) .. unbalanced reduction reaction
NO3-(aq) ==> NH3(g) + 3H2O(l) .. balanced for N and O
NO3-(aq) + 9H2O(l) ==> NH3(g) + 3H2O(l) + 9OH-(aq) .. balanced for N, O and H
NO3-(aq) + 9H2O(l) + 8e- ==> NH3(g) + 3H2O(l) + 9OH-(aq) .. balanced for N, O, H and charge
AsH3(s) ==> As(s) .. unbalanced oxidation reaction
AsH3(s) + 3OH-(aq) ==> As(s) + 3H2O(l) .. balanced for As, O, and H
AsH3(s) + 3OH-(aq) ==> As(s) + 3H2O(l) + 3e- .. balanced for As, O, H and charge
Multiply reduction rxn by 3 and oxidation rxn by 3 to equalized electrons. Add the two rxns together and combine / cancel like terms to get the final balanced redox equation:
3NO3-(aq) + 27H2O(l) + 24e- ==> 3NH3(g) + 9H2O(l) + 27OH-(aq)
8AsH3(s) + 24OH-(aq) ==> 8As(s) + 24H2O(l) + 24e-
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3NO3-(aq) + 27H2O(l) + 24e- + 8AsH3(s) + 24OH-(aq) ==> 3NH3(g) + 9H2O(l) + 27OH-(aq) + 8As(s) + 24H2O(l) + 24e-
3NO3-(aq) + 8AsH3(s) ==> 3NH3(g) + 6H2O(l) + 3OH-(aq) + 8As(s) .. balanced redox equation