Consider the given reaction. A(aq)+B(s)↽−−⇀C(aq)𝐾=9.40 Suppose 13.2 mol A reacts with excess B in 5.70 L of solution. Calculate the concentration of C at equilibrium. [C]= M

Answer 1

A(aq) + B(s) <==> C(aq) K = 9.40

[A] = 13.2 mol / 5.70 L = 2.32 M

A(aq) + B(s) <==> C(aq)

2.32.......xs.............0..........initial

-x...........................+x........change

2.32-x.....................x.........equilibrium

K = 9.40 = [C] / [A]

9.40 = x / 2.32-x

x = 21.8 - 9.40x

x = 2.10 M = [C] @ equilibrium