Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S2(g)+C(s)↽−⇀CS2(g)𝐾c=9.40 at 900 K

Question

How many grams of CS2(g) can be prepared by heating 8.89 mol S2(g) with excess carbon in a 5.05 L reaction vessel held at 900 K until equilibrium is attained?

mass of CS2(g):

g=?

Answer 1

S₂(g) + C(s)↽−⇀CS₂(g)

8.89....................0.............initial

-x.......................+x............change

8.89-x..................x............equilibrium

K = 9.40 = [CS₂] / [S₂]

9.40 = x / 8.89-x

x = 83.6 - 9.40x

x =8.04 moles CS₂

molar mass CS₂ = 76.1 g / mol

mass CS₂ = 8.04 mols x 76.1 g / mol = 612 g CS₂