J.R. S. answered 03/12/23
Ph.D. University Professor with 10+ years Tutoring Experience
5.441 g H2 x 1 mol H2 / 2 g = 2.72 mols H2
8.674 g C(s) x 1 mol C / 12 g = 0.723 mols C
C(s) + 2H2(g) ⇌ CH4(g)
0.723....2.72.......0.............Initial
-x..........-2x.........+x..........Change
0.723-x..2.72-2x...x..........Equilibrium
Kp = (CH4) / (H2)2
0.263 = x / (2.72-2x)2
0.263 = x / 4x2 - 10,88x + 7.40
0 = 0.05x2 - 2.86x + 1.95
x = 0.690 mols CH4(g)
mols H2(g) @ equilibrium = 2.72 - 2x0.690 = 1.34 mols H2(g)
Total mols gas = 0.690 + 1.34 = 2.03 mols
PV = nRT
P = nRT/V = (2.03)(0.0821)(1000) / 9.81
P = 17.0 atm
(be sure to check the math)