Determine the volume (in mL) of water that needs to be added to 50.0 mL of a 0.600 M LiBr to produce a 0.145 M solution. Assume the volumes are additive.

Answer 1

V1M1 = V2M2

(50 ml)(0.600 M) = (x ml)(0.145 M)

x = 207 mls final volume

Since began with 50 mls, need to add 207 - 50 = 157 mls