10.0 mL of water was added to 100.0 mL of 0.250 M CaCl₂ solution. Assuming the volumes are additive, what is the CaCl₂ concentration in the diluted solution?

Answer 1

V1M1 = V2M2

V1 = initial volume = 100 ml

M1 = initial molarity = 0.250 M

V2 = final volume = 110.0 ml

M2 = final molarity = ?

(100 ml)(0.250 M) = (110 ml)(x M)

x = 0.227M