The pOH of a basic solution is 5.63. What is [OH⁻]?

Answer 1

Hi Alex!

Let's begin solving! To calculate pOH, we use the following formula:

pOH = -log[OH-]

Since we were given the pOH, we can rearrange this equation to find [OH-]:

[OH-] = 10^-pOH

Using this new equation, we can plug in our given pOH to find [OH-]:

[OH-] = 10^-(5.63)

[OH-] = 2.34422882 x 10^-6 M

We have 3 significant figures from our given pOH, so:

[OH-] = 2.34 x 10^-6 M

Hope this helps! :)