
Yefim S. answered 03/02/23
Math Tutor with Experience
Perpendicular bisector of AB: (x - 3)2 + (y - 3)2 = (x - 2)2 + (y - 10)2; - 6x - 6y + 18 = - 4x - 20y + 104;
x - 7y = - 43;
Perpendicular bisector of BC: (x - 2)2 + (y - 10)2 = (x - 9)2 + (y - 11)2; - 4x + 4 - 20y + 100 = - 18x + 81 - 22y + 121; 14x + 2y = 98; 7x + y = 49; x = 7y - 43; 49y - 301 + y = 49; 50y = 350; y = 7, x = 49 - 43 = 6
(6,7) is circumcenter
It's radius R = √(7 - 3)2 + (6 - 3)2 = 5

Dayv O.
(6,7) is circumcenter, point (3,3) is 5 away from (6,7) and (7,6)03/02/23