The diagram shows two squares of side 1 unit which share a common vertex and are inclined at 45 degrees to each other. Find the area of thr overlapping region shaded in the region

Answer 1

If the shaded area is the overlap then it is equal to one-half the area of the square, s² / 2 minus the triangle that is out side of the overlap. The base is (s√2) - s and the height is s / 2

Can you compute area of triangle, subtract, and answer?

Answer 2

interesting question without the problem

but in a few minutes, I'll have it figured out. Or not. Or someone will, with or without a diagram.

whatever the answer, it's less than half the area of the square. Less than 1/2. Use a little geometry and triangles Afterall, you did get this problem posted under "geometry" and "trigonometry"

while a diagram may be useful, it's not necessary. It can be constructed from the given info.

but the geometry gets tedious

the overlapping area looks like a quadrilateral you can divide into 2 triangles and a rectangle

sum their areas and I get about 0.4745

after rounding to 4 decimal places

I'm curious though. Show us the diagram and see if I constructed the same diagram, or got the right area of an overlap. Don't hold us in suspense.

or let's hear from another tutor or two. (two-ters? two-fers?)