Eric J.

asked • 03/02/23

I'm not sure what concept this problem is getting at. What is it trying to show me? I know how to do the problem, but I'm not sure what it's trying to entail:

Triangle ABC has a 34-degree angle at A. The bisectors of angles B and C meet at point I. What is the size of angle BIC? Answer this question (a) assuming that ABC is right; (b) assuming that ABC is isosceles; (c) choosing sizes for angles B and C. Hmm . . .


Paul M.

Where is the right angle? Which sides are equal in the isosceles triangle? I don't think this question can be answered without this information.
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03/02/23

Stanton D.

Sure it can. B+C = 180 - 34. Then B/2 + C/2 = 90 -17. That leaves BIC = 180 - (90-17). It doesn't matter what B and C are individually, that's what it's trying to make you figure out.
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03/02/23

Nazlee R.

There are 3 scenarios to this question. One of the angles is a right angle, or it is an isosceles triangle, and lastly a triangle with angles measuring 34, and B, C being some degrees of choice adding upto 180 degrees. Angle BIC would be computed accordingly.
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03/05/23

1 Expert Answer

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Robert K. answered • 03/02/23

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The answers to parts (a), (b), and (c) are the same. Angles B and C will always add up to 146 degrees. (180 - 34 = 146)


Angle BCI will be one half of angle BCA.


Angle CBI will be one half of angle CBA.


Therefore angles BCI and CBI will have a sum of 73 degrees. (half of 146)


There angle BCI will be 107 degrees. (180 - 73 = 107)

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