Danny C. answered 03/02/23
PhD Math - Linear Algebra, ProbStat, Discrete, Analysis, Logic+Fitch
The 98% confidence interval for population mean is (sample mean)±2.15*(sample standard deviation s)/sqrt(n)
The sample mean is 1868 and the sample standard deviation is 1650. The sqrt(28) is about 5.29. So the confidence interval is
1868 ± 1650*2.15/5.29 = 1868 ± 671 = [1197, 2539]