J.R. S. answered 02/26/23
Ph.D. University Professor with 10+ years Tutoring Experience
2 NH₃(g) + 3 CuO (s) ==> 3 Cu(s) + N₂(g) + 3 H₂O(g) .. balanced equation
Since there is an excess NH3, we need only concern ourselves with CuO to determine how much N2 will form.
We will use the stoichiometry of the balanced equation and dimensional analysis to solve the problem:
5.36 mol CuO x 1 mol N2 / 3 mol CuO = 1.79 mols N2