The equilibrium constant for the chemical equation N2(g)+3H2(g)↽−−⇀2NH3(g) is 𝐾p=0.0501 at 211 ∘C. Calculate the value of 𝐾c for the reaction at 211 ∘C. 𝐾c=

Answer 1

N₂(g) + 3H₂(g) ==> 2NH₃(g)

Kp = Kc (RT)^∆n

Kp = 0.0501

Kc = ?

R = 0.0821 Latm/Kmol

T = temperature in K = 211C + 273 = 484K

∆n = change in moles of gas = 2 - 4 = -2

0.0501 = Kc(0.0821 x 484)^-2

0.0501 = Kc (39.74)^-2

0.0501 = Kc (1 / √39.74)

0.0501 = 0.159 Kc

Kc = 0.315