Inactive Tutor answered 06/24/26
1-PropZInt(x: 73, n: 116, C-Level: 0.80)
≈ {0.572, 0.687}
0.572 ≤ p ≤ 0.687
Justin L.
asked 02/24/23Assume that a sample is used to estimate a population proportion p. Find the 80% confidence interval for a sample of size 116 with 73 successes. Enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places.
Inactive Tutor answered 06/24/26
1-PropZInt(x: 73, n: 116, C-Level: 0.80)
≈ {0.572, 0.687}
0.572 ≤ p ≤ 0.687
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