How many atoms of phosphorus are in 7.30 mol of copper(II) phosphate

Answer 1

Write the formula for copper(II) phosphate:

Cu₃(PO₄)₂

Count the number of moles phosphorous (P) atoms in 1 mole:

(PO₄)₂ has 2 moles of P atoms per each 1 mole

Calculate moles of P atoms in 7.30 mole of Cu₃(PO₄)₂"

7.30 moles Cu₃(PO₄)₂ x 2 moles P atoms / moles = 14.60 moles of P atoms

Convert this to atoms of P:

14.60 moles P atoms x 6.02x10²³ atoms / mole = 8.79x10²⁴ P atoms

or done another way...

7.30 mols Cu₃(PO₄)₂ x 2 mols P atoms / mole Cu₃(PO₄)₂ x 6.022x10²³ atoms / mole = 8.79x10²⁴ P atoms